normalize count data from htseq
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Peter • 0
@peter-6856
Last seen 4.6 years ago
China

Dear expert,


I have got count data with htseq-count. In my study, there is no groups. Only one group, I do not want do deferential analsyis.
How can I normalize my count data?
I use code as follow, but get error.

workdir <- "~/projects/all/analysis/rnaseq/deseq2/results"
setwd(workdir)
library('DESeq2')
dat.dir<-"~/projects/all/analysis/rnaseq/count/gene/"
countFiles <- list.files(dat.dir,pattern =".txt")
library(stringr)
sampleName <- str_replace(countFiles, ".txt", "")
sampleCondition <- rep("all",length(sampleName))
sampleTable<-data.frame(sampleName=sampleName, fileName=countFiles,condition=sampleCondition)
ddsHTSeq<-DESeqDataSetFromHTSeqCount(sampleTable=sampleTable, directory=dat.dir, design=~condition)

Error in `contrasts<-`(`*tmp*`, value = contr.funs[1 + isOF[nn]]) :
  contrasts can be applied only to factors with 2 or more levels

deseq2 normalization • 4.7k views
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Entering edit mode
@mikelove
Last seen 5 days ago
United States

See the function estimateSizeFactorsForMatrix. This will estimate a vector of size factors, normalization is then just dividing each column by its respective size factor, see R's function sweep() for example.

You can also use a design of ~1, meaning there are no factors dividing the samples (I should have the function print this as a nicer message).

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Entering edit mode
Peter • 0
@peter-6856
Last seen 4.6 years ago
China

Thank you for your reply.

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